(急,在线等)请教servlet问题
我写了个servlet.java,编译后把它放在C:\Tomcat   5.0\webapps\shop\WEB-INF\classes\com\shop下,然后在jsp文件中写 <form   id= "form1 "   name= "form1 "   method= "post "   action= "FormAction "> ,为什么运行后显示The   requested   resource   (/shop/com/shop/FormAction)   is   not   available. 
 ,请高手指点一下,谢谢    
 package   com.shop;   
 import   
java.io.IOException; 
 import   java.util.Collection;   
 import   
javax.servlet.ServletException; 
 import   javax.servlet.http.HttpServletRequest; 
 import   javax.servlet.http.HttpServletResponse;     
 /** 
    *   Servlet   implementation   class   for   Servlet:   UserListServlet 
    */ 
 public   class   FormAction   extends   javax.servlet.http.HttpServlet   implements 
 		javax.servlet.Servlet 
 		{ 
 	/* 
 	   *   (non-Java-doc) 
 	   * 
 	   *   @see   javax.servlet.http.HttpServlet#HttpServlet() 
 	   */ 
 	public   FormAction() 
 	{ 
 		super(); 
 	}   
 	/* 
 	   *   (non-Java-doc) 
 	   * 
 	   *   @see   javax.servlet.http.HttpServlet#doGet(HttpServletRequest   request, 
 	   *                  HttpServletResponse   response) 
 	   */ 
 	protected   void   doGet(HttpServletRequest   request, 
 			HttpServletResponse   response)   throws   
ServletException,   
IOException  			{ 
 		response.setHeader( "Pragma ", "No-cache "); 
 		response.setHeader( "Cache-Control ", "no-cache "); 
 		response.setDateHeader( "Expires ",   0);     
 		String   name   =   request.getParameter( "name "); 
 		int   age   =   Integer.parseInt(request.getParameter( "age ")); 
 		System.out.println   ( "name=    "+name); 
 		System.out.println   ( "age=    "+age); 
 		System.out.println( "ok ");   
 	            } 
 } 
------解决方案--------------------form id= "form1 " name= "form1 " method= "post " action= "FormAction "> , 
 把post改成get看看
------解决方案--------------------你得在web.xml里配置servlet啊 
  <web-app>  
    <servlet>  
      <servlet-name> FormAction </servlet-name>  
      <servlet-class> com.shop.FormAction </servlet-class>  
    </servlet>  
    <servlet-mapping>  
      <servlet-name> FormAction </servlet-name>  
      <url-pattern> /FormAction </url-pattern>  
    </servlet-mapping>  
  </web-app>
------解决方案--------------------还有  把你的formaction改成你的servlet类名!!
------解决方案--------------------alieneagle() 正解,顶!!!
------解决方案--------------------顶一个!!!!!!!!