日期:2014-05-17 浏览次数:21430 次
private void tmp()
{
double[] dou = new double[] { 1, 2, 3, 4, 5, 6 };
DataTable dt = new DataTable();
dt.Columns.Add("temp", System.Type.GetType("System.Double"));
DataRow row;
for (int i = 0; i < dou.Length; i++)
{
row = dt.NewRow();
row["temp"] = dou[i];
dt.Rows.Add(row);
}
}
------解决方案--------------------
double[] dou = new double[] { 1, 2, 3, 4, 5, 6 };
DataTable dt = new DataTable();
dt.Columns.Add("id", typeof(double));
dou.ToList().ForEach(t => dt.Rows.Add(t));