关于datagridview代码,求指教???
private void btnSearch_Click(object sender, EventArgs e)
         {
             Dictionary<string, string[]> searchRst = new Dictionary<string, string[]>();
             for (int i = 0; i < cmbServices.Items.Count; i++)
             {
                 string stype = cmbServices.Items[i].ToString();
                 Kingtop.Esoso.ServicesSite ss = GetServiceSite(stype);
                 string lsResult = lss.GetPoi(Kingtop.Esoso.ServicesSite.MapBar, textBox3.Text, textBox1.Text);
                 Kingtop.Esoso.LsSvcPoiRst lspr = (Kingtop.Esoso.LsSvcPoiRst)Newtonsoft.Json.JavaScriptConvert.DeserializeObject(lsResult, typeof(Kingtop.Esoso.LsSvcPoiRst));
                 if (lspr == null || lspr.state == false)
                 {
                     //Error
                 }
                 else
                 {
                     Kingtop.Esoso.Poi[] pary = lspr.data;
                     string[] aryRst = null;
                     searchRst.Add(stype, aryRst);
                 }
                 //转换为datatable,并绑定
                 DataTable dt = new DataTable();
                 dt.Columns.Add("方法", typeof(String));
                 dt.Columns.Add("关键字", typeof(String));
                 dt.Columns.Add("潜力", typeof(String));
                 dt.Columns.Add("POI", typeof(String));
                 dt.Columns.Add("名称", typeof(String));
                 dt.Columns.Add("地址", typeof(String));
                 dt.Columns.Add("区划代码", typeof(String));
                 for (int i = 1; i < ********; i++)
                 {
                     string[] data = lspr.data;
                     DataRow dr = dt.NewRow();
                     dr[0] = "名址匹配";
                     dr[1] = textBox1.Text;
                     dr[2] = "名称";
                     dr[3] = "名称";
                     dr[4] = **********;
                     dr[5] = **********;
                     dr[6] = **********;
                     dt.Rows.Add(dr);
                 }
                 this.dataGridView2.DataSource = dt;
             }
         }
------解决方案--------------------
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