日期:2014-05-18 浏览次数:20996 次
create table tbtext(id int,name text) insert tbtext select 1,'a' DECLARE @ptrval binary(16),@len int SELECT @ptrval = TEXTPTR(name) FROM tbtext where id=1 UPDATETEXT tbtext.name @ptrval 1 null 'b'; select * from tbtext
------解决方案--------------------
麻烦大了,下面引用邹建写的:
--下面的代码演示, 如果把两个 text 列相加, 更新到其中一个 text 列中
USE tempdb
GO
-- 测试环境
CREATE TABLE ta(id int identity(1, 1), col1 text)
CREATE TABLE tb(id int identity(1, 1), col1 text)
INSERT ta SELECT REPLICATE('abc', 8000)
INSERT tb SELECT REPLICATE('cba', 8000)
-- show insert data length
SELECT [ta.col1] = DATALENGTH(col1) FROM ta
SELECT [tb.col1] = DATALENGTH(col1) FROM tb
GO
-- 更新 ta, 让 ta.col1 = ta.col1 + ' ' + tb.col1
-- 条件: ta.id = 1, tb.id = 1
DECLARE @p1 binary(16), @p2 binary(16)
SELECT @p1 = TEXTPTR(col1) FROM ta (NOLOCK)
WHERE id = 1
IF TEXTVALID('ta.col1', @p1) = 0
BEGIN
RAISERROR('ta.col1 invalid', 16, 1)
RETURN
END
SELECT @p2 = TEXTPTR(col1) FROM tb (NOLOCK)
WHERE id = 1
IF TEXTVALID('tb.col1', @p2) = 0
BEGIN
RAISERROR('tb.col1 invalid', 16, 1)
RETURN
END
-- insert space split
UPDATETEXT ta.col1 @p1 NULL 0 '-'
--insert tb.col1
UPDATETEXT ta.col1 @p1 NULL 0 tb.col1 @p2
GO
-- show update result
SELECT [ta.col1] = SUBSTRING(col1, 1, 10) + '...' + SUBSTRING(col1, 15988, 100),
[ta.col1_length]= DATALENGTH(col1)
FROM ta
WHERE id = 1
GO
DROP TABLE ta, tb
------解决方案--------------------
学习了。。。
------解决方案--------------------
if object_id('tbtext') is not null
drop table tbtext
go
create table tbtext(id int,name text)
insert tbtext
select 1,'a' union all
select 2,'cc'
DECLARE @ptrval binary(16),@len int
SELECT @ptrval = TEXTPTR(name) ,@len=DATALENGTH(name)
FROM tbtext where id=2
UPDATETEXT tbtext.name @ptrval @len 0 'b';
select id,convert(varchar(max),name) name from tbtext
/*
id name
----------- ----------------------------------------------------------------------------------------------------------------
1 a
2 ccb
(2