日期:2014-05-18 浏览次数:20990 次
///<summary>
///返回所需時間的完整格式 xx天xx小時xx分鐘xx秒
///</summary>
///<param name="seconds">總共所需的秒數</param>
public string LeftTimeFormat(int seconds)
{
string s = "";
if (seconds / (3600 * 24) > 0)
{
s += seconds / (3600 * 24) + "天";
seconds = seconds % (3600 * 24);
}
if (seconds / 3600 > 0)
{
s += seconds / 3600 + "小時";
seconds = seconds % 3600 ;
}
if (seconds / 60 > 0)
{
s += seconds / 60 + "分鐘";
seconds = seconds % 60;
}
s += seconds + "秒";
return s;
}