日期:2014-05-18 浏览次数:20872 次
ArrayList list = new ArrayList();
for (int i = 0; i < nodelist.Count; i++)
{
XmlNode node = nodelist[i].ParentNode;
if (node.Attributes["Sort"] != null)
{
[color=#FF0000]list[int.Parse(node.Attributes["Sort"].Value)] = node.Name.ToString();[/color]
}
}