日期:2014-05-18 浏览次数:20953 次
public List<int> GenerateNumber()
{
Random random = new Random();
List<int> number = new List<int>(9000);
List<int> result = new List<int>(9000);
for (int i = 0; i < 10; i )
{
number.Add(i);
}
for (int i = 0; i < 4; i )
{
int tempNum = random.Next(0, number.Count);
result.Add(number[tempNum]);
number.RemoveAt(tempNum);
}
return result;
}