日期:2014-05-20 浏览次数:21023 次
Match match = Regex.Match(str,"Accept:([^\r\n]+)", RegexOptions.IgnoreCase);
if(match.Success)
{
string value = match.Groups[1].Value;
}
------解决方案--------------------
(?i)Accept:.+
------解决方案--------------------
List<KeyValuePair<string,string>> keyValueList = new List<KeyValuePair<string,string>>();
MatchCollection matches = Regex.Matches(str,"Accept:([^\r\n]+)", RegexOptions.IgnoreCase);
foreach(Match match in matches)
{
string value = match.Groups[1].Value.Trim();
MatchCollection matches1 = Regex.Matches(value, @"([^=]+)=([^;]+);?", RegexOptions.None);
foreach(Match match1 in matches1)
{
keyValueList.Add(new KeyValuePair<string,string>(match1.Groups[1].Value,match1.Groups[2].Value));
}
}
foreach(KeyValuePair<string,string> item in keyValueList)
{
// 穷举keyValueList可以提取所有Accept里面的键和值
}