关于ajax问题,寻求解决办法
/*分析返回的XML文档*/   
 function   complete()   
 {   
 if   (req.readyState   ==   4)   
 {      
 if   (req.status   ==   200)   
    {      
 var   type   =   req.responseXML.getElementsByTagName( "content ");      
 var   str=new   Array(); 
 for(var   i=0;i <type.length;i++)   
 {   
 str[i]=(type[i].firstChild.data).split( "@@@ "); 
 var   kkk=str[i] 
 ////////////// 
 } 
 } 
 以下是表单中的复选框 
  <html:form   action= "/usergg.do "   method= "post ">  
  <input   type= "checkbox "   name= "aaa1 "   id= "aaa1 ">  <br>  
  <input   type= "checkbox "   name= "aaa2 "   id= "aaa2 ">  <br>  
  <input   type= "checkbox "   name= "aaa3 "   id= "aaa3 ">  <br>  
  <input   type= "checkbox "   name= "aaa4 "   id= "aaa4 ">  <br>  
  <input   type= "checkbox "   name= "aaa5 "   id= "aaa5 ">  <br>  
  <input   type= "checkbox "   name= "aaa6 "   id= "aaa6 ">  <br>  
  <input   type= "checkbox "   name= "aaa7 "   id= "aaa7 ">  <br>  
  <input   type= "checkbox "   name= "aaa8 "   id= "aaa8 ">  <br>  
  <input   type= "checkbox "   name= "aaa9 "   id= "aaa9 ">  <br>  
  <input   type= "checkbox "   name= "aaa10 "   id= "aaa10 ">  <br>  
  <input   type= "checkbox "   name= "aaa11 "   id= "aaa11 ">  <br>  
  <input   type= "checkbox "   name= "aaa12 "   id= "aaa12 ">  <br>  
  <input   type= "checkbox "   name= "aaa13 "   id= "aaa13 ">  <br>  
  <input   type= "checkbox "   name= "aaa14 "   id= "aaa14 ">  <br>  
  <input   type= "checkbox "   name= "aaa15 "   id= "aaa15 ">  <br>  
  </html:form>  
 我现在想做的是如果str[i]中循环出有等于1的,那么复选框aaa1就选择上,没有就不选,有等于2的,复选框aaa2就勾选,否则就不选,以次类推。从数据库中取出来的数据也就是type不一定有几个。请高手指教。
------解决方案--------------------document.all( "aaa " + str[i]).checked = true;
------解决方案--------------------for(var i=0;i <type.length;i++) 
 {  
   str[i]=(type[i].firstChild.data).split( "@@@ "); 
   docuemnt.getElementById( 'aaa '+str[i]).checked = true; 
 }
------解决方案--------------------up
------解决方案--------------------for(var i=0;i <type.length;i++) 
 {  
   str[i]=(type[i].firstChild.data).split( "@@@ "); 
   docuemnt.getElementById( 'aaa '+str[i]).checked = true; 
 } 
------解决方案--------------------up