日期:2014-05-17 浏览次数:20805 次
<tr> <td height="62" background="images/office_r9_c7.jpg" width="871"> <a href="of_detail.jsp?id=<%=news.getID() %>"class="pt1"> <div align="center" class="bluept"><%=news.getTITLE() %></div></a> </td> <td height="62" background="images/office_r9_c7.jpg" width="871"> <a href="of_detail.jsp?id=<%=news.getID() %>"class="pt1"> <div align="center" class="bluept"><%=news.getTITLE() %></div></a> </td> </tr>
------解决方案--------------------
每两个换行吗?
<%
for(int i =0;i<list.size();i++){
News news = (News)list.get(i);
if(i%2==0) {
%>
<tr> <%}%>
<td height="62" background="images/office_r9_c7.jpg" width="871">
<a href="of_detail.jsp?id=<%=news.getID() %>"class="pt1">
<div align="center" class="bluept"><%=news.getTITLE() %></div></a>
</td>
<% if((i+1)%2==0) {
</tr> <%}%>
<%} %>
------解决方案--------------------
楼主怎么又发一次?
<%
boolean flag = true;
for(int i =0;i<list.size();i++){
ea =(Expert_team)list.get(i);
if(flag){
%>
<tr>
<td><%=ea.getNAME()%><%flag=false;%></td>
<%}else{%>
<td><%=ea.getNAME()%><%flag=true;%></td></tr>
<%
} }
%>
------解决方案--------------------
<%
for(int i =0;i<list.size();i+=2){
// 第一列
News news = (News)list.get(i);
//第二列
if(i+1<list.size()) {
news = (News)list.get(i+1);
}else {
//<td> </td>
}
%>
------解决方案--------------------