日期:2014-05-16 浏览次数:20477 次
<table border="0" cellpadding="0" cellspacing="0">
<tr>
<td>
<select id="TypeLevel1" name="TypeLevel1" size="13" style="WIDTH: 100px">
</select>
</td>
<td style="height: 100px" width="20">
<div style="height:100%;padding-top:80px;">
<b>→</b></div>
</td>
<td>
<select id="TypeLeve2" name="TypeLevel2""
size="13" style="WIDTH: 100px">
<option value="">不选</option>
</select>
</td>
</tr>
</table>
<table border="0" cellpadding="0" cellspacing="0">
<tr>
<td>
<select id="TypeLevel1" name="TypeLevel1" size="13" style="WIDTH: 100px">
<option>1</option>
<option>2</option>
<option>3</option>
<option>4</option>
<option>5</option>
</select>
</td>
<td style="height: 100px" width="20">
<div style="height:100%;padding-top:80px;">
<b style="cursor:pointer;" onclick="move(true)">→</b><br /><br />
<b style="cursor:pointer;" onclick="move()">←</b></div>
</td>
<td>
<select id="TypeLevel2" name="TypeLevel2"
size="13" style="WIDTH: 100px">
<option value="">不选</option>
</select>
</td>
</tr>
</table>
<script type="text/javascript">
function move(toRight) {
var s1 = document.getElementById('TypeLevel1'), s2 = document.getElementById('TypeLevel2');
if (toRight) {
if (s1.selectedIndex == -1) { alert('请选择要移动的Option!'); return; }
s2.appendChild(s1.options[s1.selectedIndex]);
}
else {
if (s2.selectedIndex == -1) { alert('请选择要移动的Option!'); return; }
s1.appendChild(s2.options[s2.selectedIndex]);
}
}
</script>
------解决方案--------------------
<html>
<head>
<script type="text/javascript" src="jquery-1.8.0.js">
</script>
</head>
<body>
<table border="0" cellpadding="0" cel