日期:2014-05-16 浏览次数:20570 次
var PathSet = $(this).attr('p');
var folderPathSize = PathSet.substring(1, PathSet.length).split('/');
var folderPath = PathSet;
var arrayPath = new Array();
var num = 0;
if(folderPathSize.length > 1)
{
for(j = 0; j < folderPathSize.length; j++)
{
if(j != folderPathSize.length - 1)
{
folderPath = folderPath.substring(0, folderPath.lastIndexOf('/'));
arrayPath[num] = folderPath;
num = num + 1;
}
}
arrayPath.reverse();
}
arrayPath[num] = PathSet;
for(k = 0; k < arrayPath.length; k++)
{
alert(arrayPath[k]); //正常输出
var PathLink = $("<a>");
PathLink.append(arrayPath[k].substring(arrayPath[k].lastIndexOf('/') + 1));
PathLink.bind('click', function()
{
alert(arrayPath[k]); //输出undefined
//$(".leftBlock").remove(); //******* 需要处理的地方
});
$('#track').append(" -> ");
$('#track').append(PathLink);
}
});
//这样试试
for (k = 0; k < arrayPath.length; k++) {
alert(arrayPath[k]); //正常输出
var PathLink = $("<a>");
PathLink.append(arrayPath[k].substring(arrayPath[k].lastIndexOf('/') + 1));
PathLink.tmp = arrayPath[k]; //定义个属性,值设为array[k]
PathLink.bind('click', function() {
alert(this.tmp);
});
$('#track').append(" -> ");
$('#track').append(PathLink);
}
------解决方案--------------------
for(k = 0; k < arrayPath.length; k++)
{
alert(arrayPath[k]); //正常输出
var PathLink = $("<a>");
PathLink.append(arrayPath[k].substring(arrayPath[k].lastIndexOf('/') + 1));
PathLink.bind('click', function([color=#FF0000]此处需要传参或者将这个click方法写成闭包[/color])
{
alert(arrayPath[k]); //输出undefined
//$(".leftBlock").remove(); //******* 需要处理的地方
});
$('#track').append(" -> ");
$('#track').append(PathLink);
}
------解决方案--------------------