日期:2014-05-16 浏览次数:21038 次
结果如下:
mysql> SELECT * FROM (SELECT cid,author,COUNT(*) AS number FROM test GROUP BY cid,author) a
-> WHERE
-> 3>(
-> SELECT COUNT(*)
-> FROM (SELECT cid,author,COUNT(*) AS number FROM test GROUP BY cid,author) b
-> WHERE a.cid=b.cid AND a.number<b.number
-> )ORDER BY cid,number DESC;
+------+----------------+--------+
| cid | author | number |
+------+----------------+--------+
| 1 | test3 | 4 |
| 1 | test2 | 3 |
| 1 | test1 | 2 |
| 2 | test33 | 4 |
| 2 | test22 | 3 |
| 2 | test11 | 2 |
| 200 | 200test_nagios | 1 |
+------+----------------+--------+
7 rows in set (0.00 sec)
N就是取分组之后的最前面几个判断,N=3就是取前3个